for oracle: months_between. Start date will be equal to add_months(sysdate,-6) And . startdate, DATEDIFF(DAY,e1. date. MONTH_START_DATE > DATEADD (MONTH, -1, h. Difference of two dates in months. This function adds a specified number of days, months, and years to a given date. - Find the “date_diff” in hours and multiply it by “60”. . Should I change (edit) the title or delete and re-post the question properly? This is what I'm addressing. 032258 the problem lies in the fact that a month is a nebulous thing - it is not a precise number of days. (You can also subtract fractions of days, but that might be outside the scope of this answer. 2. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate. , SYSDATE - pr. This is from my own library, will return the difference of months between two dates. TIMESTAMP Functions. The unit of time. Both integer (int) and big integer (bigint) are numeric data types used to store integer values. datediff isn't a function in Oracle. 15 minutes. This is because the two dates are exactly 24 hours apart. SELECT {sales} ON COLUMNS, Filter( [Time dimension]. select dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,getdate() )+1, 0)) Last Day of Current YearRemarks. Then, we need a 2-digit month string. StartDate) AND. last_day (feb) to last_day (mar) is also commonly accepted as a "month". Can be one of the following values:Step-7: SQL Query to Calculate the Number of Months between two specific dates : Now let’s find the number of months between the dates of an order of ‘Maserati’ and ‘Ferrari’ in the table using the DATEDIFF () function. The MDX DateDiff function for Essbase returns the difference (a number) between two input dates in terms of the specified date-parts, following a standard Gregorian calendar. The NEXT_DAY() function accepts two arguments:. (Query using SQL server 2005 and 2008 is allowed). You get the difference in days. SELECT DATEADD(WEEK, DATEDIFF(WEEK,0,GETDATE()),-3) Executes. Beneath the plainness of its name, it hides a little depth. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. The recommended solution on Stack Overflow for example is this. Here's how it does this: First the DATE function creates the date, 5/1/2016. = Duration. Suppose, InstallDate is 1st of the month (if falls on Saturday) and CompleteDate is 16th of the month (if falls on Sunday) In that case, actual Business Days is 10 but the marked query result will give the answer as 12. Usage Notes¶. So, the difference between Jan 1 20015 and Dec 31 2016 is 1 year. Modified 3 years, 2 months ago. Returns. Oracle Month to Date:Showing data 6 months greater than date parameter?? 607634 Mar 24 2010 — edited Mar 24 2010. The math is 100% accurate for dates within a couple of hundred years or so. Adds days, months, and years to the date and returns the result. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input dates. You can write the query in a SQL statement using the DATEADD and DATEDIFF() function. I suggest to use "months_between" function because it takes leap years into account (months_between wants 2 dates as parameters): select months_between(sysdate, to_date('1994-08-13', 'YYYY-MM-DD'))/12 from dual; 26,4729751904122. ) Description It's easy to do date arithmetic in Oracle Database, but it can be hard to remember the formulas. 1. sql. When the reporting date month is the same as the target month you can get a round up To get the number of month or day, you change the first argument to month or day as shown below: Notice that the DATEDIFF () function takes the leap year into account. If the resulting date would have more days than are available in the resulting month, the result is the last day of that month. Purpose MONTHS_BETWEEN returns number of months between dates date1 and date2. The days are in two different, adjacent months, so the answer is 1 month difference. Oracle's MONTHS_BETWEEN on the other hand tries to calculate an exact difference in months' fractions: select months_between(date '2021-02-01', date '2021-01-31') from dual; => 0. If both inputs are unknown time zones, then the DateDiff will be calculated on both Dates as if they were defined in the same time zone. SQL> ed Wrote file afiedt. select months_between(date '2015-03-19', date '2012-01-06') as month_diff from dual; MONTH_DIFF ----- 38. Specifically, it gets the difference between 2 dates with the results returned in date units specified as years, months days, minutes, seconds as a bigint value. Weeks. 8494441'. YEAR: Stores the year information only, either in 2-digit or 4-digit format. g. Oracle 9i and later versions support CURRENT_DATE and CURRENT_TIMESTAMP. 1. Before using this function, you must set the NLS_DATE_FORMAT parameter to display 24-hour time. @Mohit224 - If you are saying that you want to ignore any fractional part of a year, then you. Getting the 1st day of the month is simpler: select dateadd (day,- (day (current_timestamp)-1),current_timestamp) From your reference point-in-time, subtract (in days), 1 less than the current day-of-the-month component. How To turn a string with "pipe-separated" values into individual rows in Oracle PL/SQL. The function supports units of years, quarters, months, weeks, days, hours, minutes, seconds, milliseconds, microseconds, and nanoseconds. Syntax. There are MANY way to compute the number of years between two dates in Oracle SQL. It should have been DATEDIFF NOT DATEADD with respect to the WEEK parameter. I am trying to come up with a way in Oracle to calculate the difference between dates in days. The DATEDIFF function will return the difference count between two DateTime periods with an integer value whereas the DATEDIFF_BIG function will return its output in a big integer value. SQL DATEPART. Date. g. One option that avoids needing to add EndDate + 23:59:59. 0 for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query . 1. select DATEADD(MONTH,1350,0) will give 2012-07-01 00:00:00. members, Datediff( GetFirstDate([Time dimension]. Feb-N to Mar-N is commonly accepted as a "month". however using the below sql statement im getting. So if there are two dates separated by one day, the year difference can be 1 (see select datediff (year, '20141231', '20150101') ). DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) (sql) The DATEDIFF() function accepts three arguments: date_part, start_date, and end_date. 一重引用符で囲んだ'YYYY-MM-DD[*HH:MI[:SS]]'形式の文字列(*はコロン(:)または空白でも可)、または現在の日付を返す引用符なしの@DATENOW. We will be using the same employees table in order to demonstrate the intricacies of calculating the difference between two dates in terms of weeks, months, or years using MySQL’s DATEDIFF() function. Hi tom, I want day, month, minute and years difference everyting in seconds. 16. date]-90) - my comparison subtracts 90 days from the max date Yes, I know,. So, we have to treat this type of cases too, which I usedMONTHS_BETWEEN = 1. Firstly, for example, it doesn’t really hold a date, instead it records a datetime. This question is asked many times and one of the suggested queries to get months between 2 dates is not working. Dynamic views containing Date, Time, or DateTime fields must be wrapped with the appropriate meta-SQL. JohnD JohnD. (year/month/date from date) //oracle function for extracting values from date. ToDate)); My SQL to LINQ Recipe might help you with some translation issues in the future. DATEENTERED ,* from sometable S where S. CODE = 'CONTACT_CLIENT' THEN a. The following shows the syntax of the DATEPART() function: DATEPART ( date_part , input_date ) Code language: SQL (Structured Query Language) (sql) The DATEPART() takes two arguments: date_part is the part of a date to be extracted. datediff() is not giving tHe result as I am working in Oracle. MySQL :: MySQL 5. We’re calculating months of service in this example. 15 between 2 values that are 1 year, 1 month and 15 days apart. 10 Answers. ROUND(p1) ROUND(p1, p2) Not Available. The first one involves getting the difference in days and then converting it to 'x year y month z days'. Then use these rules to set the column values: Start date: for the first row, return the input date; otherwise return the first of the month; End date: get the month start for the next row and subtract one day from it. The expression is given to calculate the month’s difference between two dates, use the date diff expression as shown below. DATEDIFF with examples DATEDIFF function accepts 3 parameters, first is datepart (can be an year, quarter, month, day, hour etc. date. NEW_TIME (date, timezone1, timezone2) Timestamp. DateDiff: 2つの日付間の間隔数を戻します。 DatePart: DatePart(inverval,date[,firstdayofweek[,firstweekofyear]]) DateSerial: DateSerial(year,month,day) Day: 月の日(1から31まで)を表す数字を戻します。 Hour: 日の時間(0から23まで)を表す数字を戻します: IsDateThe easiest solution (ignoring leap years and whatnot) is to use DATEDIFF. The datepart value cannot be specified in a variable, nor as a quoted string like 'month'. It counts the number of year boundaries between two dates. It creates it using the year in cell E17, and the month in cell E17. The value returned is always of data type DATE, even if you specify a different datetime data type. If date1 and date2 are either the same days of the month or both last days of months, then the. Note that SQL Server DATEDIFF(month, date2, date1) function does not return exactly the same result, and you have to use an user-defined function if you need to fully emulate the Oracle MONTHS_BETWEEN function (see. I want to select some data from one table if a date from another table is at least 6 months before today. Assuming that a. Formats timestamp as a string using format. NET SQL Added in; EF. If either expression is a character or graphic string, it must not be a CLOB. If you enter a negative parameter, the system subtracts the specified days, months, or years. SQL Query with Dates. PeopleTools uses the SQL directly from the view definition (view text) and doesn't generate anything, so no meta-SQL wrapping is done. Third, the more verbose method. date + time. I recommend you have a stab yourself. The Oracle ROUND () function takes two arguments: 1) date. You also wouldn't prefix a function name with the @ sign. Recall that earlier I mentioned that in my example I. That is, this function returns the count (as a signed integer value) of the specified datepart boundaries crossed between the specified start date and end date. DATE_ADD () Add time values (intervals) to a date value. SELECT --Start with total number of days including weekends (DATEDIFF (dd,@StartDate,@EndDate)+1) --Subtact 2 days for each full weekend (DATEDIFF (wk,@StartDate,@EndDate)*2) --If StartDate is a Sunday, Subtract 1 ELSE 0 END) --If EndDate is a Saturday, Subtract 1 FROM dual. The Question asked for "6 months from the system date". 0208 days. ADD_MONTHS. We will use the below date for the examples. The days are in two different, adjacent months, so the answer is 1 month difference. How can I calculate the date difference between these 2 columns? sql; sql-server-2008; t-sql; datediff. That prevents. (You can also subtract fractions of days, but that might be outside the scope of this answer. Now it only runs DateAdd () once, and it can use an index (if one exists), to only load the rows that match the predicate criterion. In short. Apr 2, 2013 at 6:13. For example, only one set of /*+ */ is allowed. Here is some T-SQL that gives you the number of years, months, and days since the day specified in @date. So, Feb-28 to Mar-28 is a month. If you enter a negative parameter, the system subtracts the specified days, months, or years. datediff('MONTH', pr. Oracle's database does not have (nor need) a datediff() function. Join our newsletter and get access to exclusive content every month. two-digit days. mysql> SELECT something FROM tbl_name-> WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) <= date_col; The query also selects rows with dates that lie in the future. 構文 @DATEDIFF (' difference ', ' date ', ' date ') difference. Select between two months. For a complete reference to SQL expressions, go to the Oracle website (requires Oracle account activation). The datediff function can return the difference between two dates in days, months, years, minutes, etc. DATEDIFF is wrong. Share. 6789' SECOND (2,3) Rounded to 15. 1. If you want an integer. Modified 1 year, 8 months ago. Gets the number of intervals between two DATE values. StandardDeviationPopulation(group. SELECT DATEDIFF (MONTH, '1/1/2014', '12/31/2014') and SELECT DATEDIFF (MONTH, '1/1/2014', '12/30/2014') both return 11. It can be used to do date math as well. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. PostgreSQL. month). Dates are always a joy to work with in any programming language, SQL not excluded. 5 Answers Sorted by: 65 I'd use months_between, possibly combined with floor: select floor (months_between (date '2012-10-10', date '2011-10-10') /12) from dual;. DateAdd. e it takes the quarter in which the start date exists and subtracts it from the quarter in which the end date exists. Calculates the difference in days between the two dates. where (year(getdate())-year(birthDate)) = 17. *Or even the CTIME. answered Oct 19, 2016 at 9:38. 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. I have a definition query defined on a feature class coming from an Oracle SDE where a date field is queried to return values within 6 months of the current date (see below) RELDATE_DATE > ADD_MONTHS (TO_DATE (SYSDATE),-6. The %DateAdd meta-SQL function returns a date by adding add_days to date_from. Next to calculate a month of services in a company by a user we would use ‘m’ to calculate the difference value. Currently I am only returning 1. hh is a two digits of hour (00 through 23). As per the methodology used in this date calculator, a week starts on 'Monday' and ends on 'Sunday'. You also wouldn't prefix a function name with the @ sign. 850". Of course, if you need days instead of months, you can simply subtract one date from another, e. Answer: Oracle supports date arithmetic and you can make expressions like "date1 - date2" using date subtraction to get the difference between the two dates. 9. Transact-SQL. Just divide the total by 7 to get the weeks and then calculate the remaining days. Syntax. select. Here’s the syntax for the DATEADD function: DATEADD (interval, number, date); The interval. ) and rest are two dates which you want to compare. date_from, evnt. The MONTHS_BETWEEN function returns an estimate of the number of months between two arguments. Each Standard calendar week is defined to start on Sunday and it spans 7 days. DATEENTERED between dateadd (mm, datediff (mm, 0, dateadd (MM, -1, getdate ())), 0) and dateadd (ms, -3, dateadd (mm,. And then we need to convert the output of DATEPART to a 2-digit month number. One truncates a date to the precision specified (kind of like rounding, in a way) and the other just returns a particular part of a datetime. DatePart. Apr 5, 2021 at 15:55. join our newsletter and get access to exclusive content every month. A) Get the difference in months of dates on the same day. Author. This works because you have no issue with months and years or one-digit vs. DATEADD ('week', 1, [due date]) Add 280 days to the date February 20, 2021. In Oracle SQL, I want to display the difference between two dates in the format 'x years y months z days'. 'month' or month). The date calculator calculates the difference between the 'Start Date' and 'End Date' and displays it in terms of the number of years, months, weeks and days between them. {"payload":{"allShortcutsEnabled":false,"fileTree":{"inst/csv":{"items":[{"name":"jarChecksum. DATEDIFF(datepart, startdate, enddate) Parameters. I have a question though. The DATEPART () function returns an integer value that represents a specified part of the date of a given date. it returns the difference in days if datepart is day. However, The. There are several date functions (DATENAME, DATEPART, DATEADD, DATEDIFF, etc. 1,984 1 1 gold badge 17 17 silver badges 31 31 bronze badges. 一重引用符で囲んだ'YYYY-MM-DD[*HH:MI[:SS]]'形式の文字列(*はコロン(:)または空白でも可)、または現在の日付を返す引用符なしの@DATENOW. Select name,surname,datediff(YY,birthDate,getdate()) as age from students order by age. 65. 2903225806 DATE_DIFF =. SYSDATE is already a date. public static int MonthDiff (DateTime d1, DateTime d2) { int retVal = 0; // Calculate the number of years represented and multiply by 12 // Substract the month number from the total // Substract the difference of the second month and 12 from the total retVal. I want to calculate the current Age from Date of Birth in my Oracle function. StartDate,. 8494441'. Consider SQL Server function to calculate the difference between 2 dates in months: SQL Server : -- Difference between Oct 02, 2011 and Jan 01, 2012 in months SELECT DATEDIFF ( month, '2011-10-02', '2012-01-01') ; -- Result: 3. We are now using NHibernate to connect to different database base on where our software is installed. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. [proc_datediff] ( @date datetime ) as begin DECLARE @diff varchar(70) DECLARE @tmpdate datetime, @years int, @months int, @days int SELECT @tmpdate = @date SELECT @years =. PostgreSQL. mm is a two digits of minute (00 through 59). Compare dates problems. Subtracts a specified time interval from a DATE value. This is so as for the ease of use later for php. 1. 9. T was trying do calculate age as on todays date in ORACLE but after a lot of brain storming i didn't get it. That link is not for the Oracle database, it's for JavaDB (Derby). g. Problem. We’re calculating months of service in this example. Simply i need to convert this: SELECT FLOOR(DATEDIFF(NOW(),`startdate`)/365. Hi team i need to get the exact month differences between two dates i am using oracle sql for my project . *Subtract the two date values, divide by (60 seconds * 60 minutes *. To get the start and end dates of each month within a given range, when the value of the @StartDate parameter is not the first day of the month: The first option is to truncate the @StartDate parameter to the. In this, we will add the number of years that we expect this person to turn in a given year, based on the DATEDIFF( ) results. So it's not an accumulative difference, it's only when a date is within a smaller month. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). Multiply by 24 -- hours, multiply by 60 minutes, multiply by 60 -- seconds. Oracle-compatible TO_CHAR function that can format a timestamp, a number. The Days, Months, and Years parameters can be negative or positive. The system calculates the number of complete months between given dates. this will give you the first of the month for a given date. The result is formatted according to the Format parameter. CREATE OR REPLACE FUNCTION dateDiff ( p_dt1 IN DATE, p_dt2 IN DATE ) RETURN NUMBER IS BEGIN RETURN p_dt1 - p_dt2; END; It's not obvious, though, what benefit you derive from doing this rather than simply. What this allows you to do is pass in two TIMESTAMP or DATETIME values (or even DATE as MySQL will auto-convert) as well as the unit of time you want to base your difference on. Viewed 32k times. This function is not sensitive to the NLS_CALENDAR session parameter. Would give you rows where date2 (the later date) is 60 to 90 days later than date1. For formatting functions, refer to Section 9. ADD_MONTHS returns slightly different results than DATEADD used with a MONTH component:. 6222691' DECLARE @date2 datetime2 = '2022-01-14 12:32:07. 25)) AS `numberofemployees`. 3. Instead, you can use simple arithmetic with Oracle dates, where subtracting one date from another gives the number of days, and where you can add an subtract days from a given date. format_datetime(timestamp, format) → varchar. MONTHS_BETWEEN gives the number of whole months between the 2 dates, and calculates the fractional part as the remainder in days divided by 31. You can even find the number of hours, minutes, seconds, and so on in terms of details in between the two. Finally, we will use a CASE statement. datepart: It is the part of the date like day, month, year, week, etc. i need to find the difference of two dates as the number of months: find the last day of the month of both the dates. For example the difference between 1st March 2011 and 3rd March 2012 is 1. 1. To calculate the number of days between date1 and date2, you can use either Day of. MonthDiff = DateDiff ("m", startdate, enddate) End If. 997268 (0 year + 365/366 years) So, in summary, the output (in DECIMAL (7,6)) from the above two examples would be: 1. CurrentMember), Today(), DP_MONTH ) < 6 ) ON ROWS FROM Mysamp. Now for testing purposes I need to compare the data for the last say 4 months from the sysdate. 3. Just out of curiosity, have you paid the $95 for a manual yet? ;-) If not, get the thicker one when you do unless you are pretty familiar with the commands and just need a reference. date_from, evnt. If you really want 'datediff' in your database, you can just do something like this: Now, i just create a view to demonstrate with: SQL> select datediff ( 'ss', d1, d2 ) seconds from temp_view; SECONDS6269539. 25) AS `years`, COUNT(FLOOR(DATEDIFF(NOW(),`startdate`)/365. The weekday (dw) datepart returns a number that. 首先在oracle中没有datediff ()函数. Improve this answer. 5 = 0. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. DateGroup. StartDate, SYSDATE) you would use: MONTHS_BETWEEN(pr. You don't need to generate all the days as it'll be inefficient; just use a recursive sub-query factoring clause to iterate over each month: WITH months (. Oracle doesn't have a DATEDIFF() function. DATE () Extract the date part of a date or datetime expression. This conversion uses the NLS_DATE_FORMAT parameter to decide the format of the output string. date1. You can even find the number of hours, minutes, seconds, and so on in terms of details in. To compare dates in SQL, the most common functions used are DATEDIFF, DATE_ADD, DATE_SUB, and NOW. The dateadd function adds or subtracts a number of specified time units from a given date. But your query is giving the last date of previous month. MySQL DATEDIFF: Calculating weeks, months, or years between two dates. 999 is to not use the between comparison and instead use column_name >= @StartDate and column_name < @EndDate +1. Example 2. DateGroup. The result only contains the year, month and day, not the time. 3. Get the number of months between two dates. SS: 差異を秒数で計算します。. This is going to be short:. buf 1 declare 2 total_days integer; 3 total_weeks integer; 4 remaining_days integer; 5 begin 6 total_days := date '2014-12-16' - date '2014-12-01'; 7 total. inner select select DATEDIFF(MONTH, 0, GETDATE()) will give the number of months from 1900-01-01 here it is 1350. SQL is a standard language for storing, manipulating and retrieving data in databases. EXE. Otherwise, the resulting date has the same day component as. January 30, 2004 - 7:26 pm UTC. This question was incorrectly asked. +1 EndDate + 23:59:59. Unfortunately, Oracle SQL doesn't allow the DATEDIFF function. If date1 is later than date2 , then the result is positive. If year numbers are different calculation of 52 * year difference + week number. The return type is always DATE, regardless of the datatype of date. Table 9. The DATEADD() function adds or subtracts a specified time interval from a date. 00. SQL Server has a nice function called DateDiff which takes a date part, startdate and enddate. select distinct e1. startdate: The first date or datetime value. 2903225806. 2258064516 DATE_DIFF = 1. This post has been answered by 630199 on Jun 1 2009. Oracle doesn't have a DATEDIFF() function. current_time() returns the date and time on the database client side. Kindly tell me how to calculate age as in years month days. If you omit fmt, then date is rounded to the. Fractions are allowed; you can add 2. * 12 + (Extract(Month From CDate(EndDate)) - Extract(Month. 2. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). 2903225806. It counts the number of year boundaries between two dates. 000 which is the start of the. Return the current time. Basic WHERE (Actual,. Just to clarify SQL server seems to require DATEDIFF (datepart, recentDate, olderDate) as startdate and enddate are a bit nebulous. Here is some T-SQL that gives you the number of years, months, and days since the day specified in @date. subtract and give the difference in number of. You may have to re-cast to a DATE datatype first. So, it starts with RIGHT(“00”. txt","contentType":"file"},{"name. As shown clearly in the result, because 2016 is the leap year, the difference in days between two dates is 2×365 + 366 = 1096. Add one date to or subtract it from another, as in l_hiredate - SYSDATE. (Oct 10, 2006 - June 14, 2005 = 69) SELECT months_between ( date_1, date_2 )/12 years_between FROM employee. SHOW_DAY is an alias to store the day. Oracle SQL - CASE in a WHERE clause. AccountNumber AND T2. 208333, so the value is correct! So now that we know how subtracting dates. DateDiffDay (r. TZD is a time zone designator ( Z, + / - hh: mm or + / - hhmm ). * , dd. startdate, SYSDATE) Keep in mind that MONTHS_BETWEEN() will return fractions of months, so use TRUNC() or ROUND() if you need an integer number. Just to make the warning explicit to everyone looking at this answer: the subquery SELECT ROW_NUMBER() OVER ( ORDER BY c. Move the start date to the next Monday, then add the calculated weeks. Syntax. then if day/month of dob is less than. sql-server. 利用日期间的加减运算. 0- 64bit Production With the Partitioning and Data Mining options'. You can write the query in a SQL statement using the DATEADD and DATEDIFF() function. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). g. DATEPART function is used to return a part of a given date in a numeric value. The Days, Months, and Years parameters can be negative or positive. Parameter Description; date1, date2: Required. DECLARE @yourDate DATE = '20160229' select DATEADD (MONTH, DATEDIFF (MONTH, -1, @yourDate)-1, -1) Just a note: this does remove any time portion in the input date, which may or may not be desired. Sample table: ProductID Date P101 31-DEC-2012 P102 29-DEC-2011So, for example: WHERE date2 - date1 BETWEEN 60 AND 90. The expression is given to calculate the month’s difference between two dates, use the date diff expression as shown below. 1. ArrivalDate, Trips. * FROM #HRAL h INNER JOIN #LAZY_DATE_DIM dd ON dd. 1) date. Hi Ive been having an issue with getting the correct difference in a date from the current month not including the day.